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PHP-如何以POST形式发送XML数据,PHP如何接收XML文件?

 ·  ☕ 1 min read  ·  🧑 WYT

PHP如何以POST形式发送XML数据,PHP如何接收XML文件?

发送XML文件: postXml.php

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$xmlData = "
<xml >ad775b217</ToUserName>
<FromUserName >tWy3zC3xUgQMR5coXif5SA</FromUserName>
<CreateTime >1366181013</CreateTime>
<MsgType >text</MsgType >
<Content >我的测试</Content >
<MsgId >5867702771251151243</MsgId >
</xml >";

第一种发送方式,也是推荐的方式,使用 curl:

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$url = 'http://cnwyt.net/xml/getXml.php';  //接收xml数据的文件
$header[] = "Content-type: text/xml";        //定义content-type为xml,注意是数组
$ch = curl_init ($url);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $header);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $xmlData);
$response = curl_exec($ch);
if(curl_errno($ch)){
    print curl_error($ch);
}
curl_close($ch);

第二种发送方式:

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$url = 'http://cnwyt.net/xml/getXml.php';
$header[] = "Content-type: text/xml";//定义content-type为xml
$server ='http://wang.net/';
$contentLength = strlen($xml_data);
$fp = fsockopen('127.0.0.1', 80);
fputs($fp, "POST $url HTTP/1.0\r\n");
fputs($fp, "Host: $server\r\n");
fputs($fp, "Content-Type: text/xml\r\n");
fputs($fp, "Content-Length: $contentLength\r\n");
fputs($fp, "Connection: close\r\n");
fputs($fp, "\r\n");     // all headers sent
fputs($fp, $xmlData );
$result = '';
while (!feof($fp)) {
    $result .= fgets($fp, 128);
}
var_dump($result);

接收XML文件: getXml.php

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//$xml = $HTTP_RAW_POST_DATA;
$xml = $GLOBALS['HTTP_RAW_POST_DATA'];
//将xml数据写入文本文件"a.txt"中
$handle  = fopen('a.txt','a+'); 
fwrite($handle,$xml);

问题:为什么不使用$_POST接收?

解答:由于PHP默认只识别 application/x-www.form-urlencoded 标准的数据类型,对型如 text/xml 的内容无法解析为 $_POST数组,故保留原型,交给 $GLOBALS['HTTP_RAW_POST_DATA'] 来接收。
注意,$HTTP_RAW_POST_DATA 对于 enctype="multipart/form-data" 表单数据不可用。

扩展阅读:

使用PHP CURL的POST数据
http://www.nowamagic.net/librarys/veda/detail/124

$HTTP_RAW_POST_DATA
http://www.cnblogs.com/xwblog/archive/2011/12/23/2299672.html

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